Mathematics : PU-CET (U.G) 2015 Panjab University Entrance Exam With Answers

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4.

Let f (x) = x$^2$ - 2x - 3 , g(x) = f(|x|). The number of solutions of g(x)=0 is/are :

A: 2
B: 3
C: 4
D: 0

The answer is: A

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